Arturo O. answered 10/03/16
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Try using the logarithmic derivative.
y = Bat
(B, a are constants)
Take ln() on both sides:
ln(y) = lnB + t ln(a)
Take d/dt on both sides:
(1/y) dy/dt = ln(a)
dy/dt = ln(a) y = ln(a) Bat
Apply this to get the derivative of your function
P(t) = 300 (1.044)t
with B = 300, a = 1.044
Feel free to post a comment if you need more help.
Arturo O.
P'(t) = ln(a) Bat
a = 1.044
B = 300
P'(t) = ln(1.044) * 300 * (1.044)t
P'(5) = ln(1.044) * 300 * (1.044)5
Yes, your answer is correct.
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10/04/16
Olivia B.
oh okay. Thank you. I'm a little slow on this material.
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10/04/16
Arturo O.
Interpretation:
The number P'(5) that you get is the instantaneous rate at which the population is changing at the moment 5 years have elapsed since the beginning of the study. The rate of change is itself also changing in time.
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10/04/16
Olivia B.
10/04/16