Arthur D. answered 10/02/16
Tutor
4.9
(285)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
2*4*6*8*10*12*....*(2n-2)*(2n) where n represents the first n even integers
factor
2*1*2*2*2*3*2*4*2*5*2*6*...*2*(n-1)*2*n
there are n number of 2s being multiplied which means 2^n
2^n*1*2*3*4*5*6*...*(n-1)*n
(2^n)(1*2*3*4*5*6*...*[n-1]*n)
(2^n)(n!)
Ian G.
10/02/16