
Kenneth S. answered 10/02/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
Hint: one million = 106 = 2x
Taking common (base 10) logs, 6 = x(log 2)
6 = x(0.30103)
x = 6/0.30103) = 19.93, approximately
So one million is a bit less than 220 which means it would fit in 20 bits.
This is reasonable since 16,777,216 is 224 -- a fact that I memorized in April 1964 when the maximum memory address of System 360 was announced.