If the line contains the points (1,a) and (3,b), then the slope of the line is (b-a)/(3-1) = (b-a)/2 = -2. So, b-a = -4
If a line contains the points (1,-a) and (3,-b), then the slope is (-b-(-a))/(3-1) = (-b+a)/2
= -(b-a)/2 = -(-4)/2 = 2