what is the equation & answer?

Question

The original price p for a necklace is the same at two jewelry stores.At store A, the sale price is 60% of the original price.Last month at Store B, the sale price was $40 less than the original price. This month at Store B, the necklace is 80% of last month's reduced price. The current sale prices are the same at both stores. What is the original price of the necklace?

Answer 1

Here's what we know:

.6p = .8(p - 40) (at store A, the price remains at 60%. At store B, the price was slashed by$40, then sent to 80% of that new price. They now the same (or equal) price.

 

Distribute:

.6p = .8p - 32

Subtract .8p from both sides:

-.2p = -32

Divide by -.2:

p = 160

 

Check:

.6 * 160 = .8(160 - 40)

96 = .8(120)

96 = 96

 

 

Answer 2

.6x = .8(x - 40)

.6x = .8x - 32

-.2x = -32

x = 160

 

$160