
Bruce B. answered 01/16/14
Tutor
4.8
(4)
Mathematics and Physics; Calculus and Mechanics Specialty
Actually, the only point where 0.5x2 and 2x2 are evenly spaced from x2 is at x = 0.
This is found by taking the difference between x2 and the other equation at any given point
|2x2 - x2| and |0.5x2 - x2|
And then setting them equal to each other.
|2x2 - x2| = |0.5x2 - x2| → x2 = 0.5x2 → x = 0.5x
And then setting them equal to each other.
|2x2 - x2| = |0.5x2 - x2| → x2 = 0.5x2 → x = 0.5x
But that isn't your question. Numbers always have patterns, so let's see if we can find this one. :)
Using the same functions, we can make a table to look at how things are spaced. I'll be going up in increments of 1, starting at 0.
0.5x2 | x2 | 2x2 | 2x2 - x2 | x2 - 0.5x2
Using the same functions, we can make a table to look at how things are spaced. I'll be going up in increments of 1, starting at 0.
0.5x2 | x2 | 2x2 | 2x2 - x2 | x2 - 0.5x2
0 | 0 | 0 | 0 | 0
0.5 | 1 | 2 | 1 | 0.5
2 | 4 | 8 | 4 | 2
4.5 | 9 | 18 | 9 | 4.5
8 | 16 | 32 | 16 | 8
So there's our pattern. Comparing just the last two columns, we see that for each increment the difference is doubled. This makes sense because the difference between 2x2 and x2 is twice as large as the difference between 0.5x2 and x2.
I hope that helped!
I hope that helped!
George H.
01/18/14