i dont understand which way it would open! /;

General rule:

y = a(x-h)^{2}+k opens up for a > 0, and down for a < 0.

x = a(y-k)^{2}+h opens right for a > 0, and left for a < 0.

Using this rule, your equation opens right.

i dont understand which way it would open! /;

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General rule:

y = a(x-h)^{2}+k opens up for a > 0, and down for a < 0.

x = a(y-k)^{2}+h opens right for a > 0, and left for a < 0.

Using this rule, your equation opens right.

This is a parabola of the form x = Ay^{2}, where A is any real number except 0. If A is positive (3 in this case), the parabola opens to the right. If it is negative, it opens to the left.

This one opens to the right.

It opens to the right because as y approaches +/- infinity, x approaches +infinity.

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