This is a math question

Question

If 6 Is Subtracted From The Third Of Three Consecutive Odd Integers And The Result Is Multiplied By 2, The Answer Is 23 Less Than The Sum Of The First & Twice The 2nd Of The Integers.

Answer 1

let's consider

 

first odd number = x

second odd number = x+2

third odd number =x+4

 

6 Is Subtracted From The Third Of Three Consecutive Odd Integers :x+4-6

And The Result Is Multiplied By 2:= 2(x+4-6) =2(x-2)=2x -4

 

The Sum Of The First & Twice The 2nd Of The Integers.:= x +2(x+2)=x+2x+4=3x +4

 

The Answer Is 23 Less Than The Sum Of The First & Twice The 2nd Of The Integers.

 

3x+4 -23 =2x -4

 

3x -19 = 2x -4

 

x = 15