Adam V. answered 09/21/16
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Let A = the first integer
Let B = the second integer
Let C = the third integer
We know the numbers are consecutive and even, so we know that
B = A + 2
C = B + 2 = A + 4
We also know that
A + B + C = 60
Since we have 3 equations and 3 variables, we can solve. Using substitution, plug B = A+2 and C = A+4 into the second equation:
A + (A + 2) + (A + 4) = 60
Now solve for A:
3*A + 6 = 60
3*A = 54
A = 18
Therefore A= 18, B = 20, C = 22