Tom D. answered 01/16/14
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Very patient Math Expert who likes to teach
Funny but interesting question.
The key to this is to realize that two events are possible
1)Riemann guy sits in his correct seat
2)Riemann guy does not sit in his correct seat
P1=1/100
P2=99/100
P100: Probability that 100th guy gets correct seat
If(P1), then P100=100% since everyone finds his correct seat
If(P2), then P100=1/99 since it will be a random chance that P100 will get his correct seat.
Using conditional probability
P100=P1*1 + P2*(1/99)=.01 + 99/100*1/99)=0.021
P100=2%
1: I'm not 100% confident with this, but it feels correct. Even if Riemann guy fails, there is still a chance that the others will fail to find the 100th guys' seat.
Update!
This has been bugging me all day. I think the answer is closer to 50% after further thought. I started with 2 seats and added an additional seat to work through the sample spaces. It is not uniformly 50% independent of #seats, but approaches this answer asymptotically. Still working on it ;-) Nice problem!!
Final Answer: I'm convinced - the answer is 50% regardless of how many seats - excellent problem.
Jyothi C.
01/18/14