Phil S.

asked • 09/09/16

Find the limit of the function.

Find the limit
lim   (5(e^−x) + 6)/(6(e^−x) + 5) 
x→∞

For questions like this I was taught to look at the starting coefficients, but I don't know how to do that when e is involved. I thought maybe the e's and their factors cancel and it was 5/6 but that was wrong. Could you please show me how to do this problem?
Thank you.

2 Answers By Expert Tutors

By:

Phil S.

so what happened from here limx→∞[(5/e^x+6)/(6/e^x+5)] to here = (0+6)/(0+5)?
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09/09/16

Mark M.

tutor
As x→∞, ex→∞.  So, as x→∞, c/ex→0, for any constant, c.
 
So, 5/eand 6/ex both approach 0 as x →∞.
 
Mark M (Bayport, NY)
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09/09/16

Michael J.

I was aware when I graphed this.  I used another approach in my answer.
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09/09/16

Michael J. answered • 09/09/16

Tutor
5 (5)

Applying SImple Math to Everyday Life Activities

Phil S.

That's what I thought would happen but it didn't accept 5/6 as an answer
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09/09/16

Mark M.

tutor
L'Hopital' Rule does NOT apply!  The limit is not of the form 0/0 or ∞/∞.
 
Mark M (Bayport, NY)
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09/09/16

Michael J.

Okay.  There is another approach it L"Hospital fails.  We rewrite the original function so that is contains positive exponents.
 
[(5 + 6ex) / ex] / [(6 + 5ex) / ex] =
 
(5 + 6ex) / (6 + 5ex)
 
 
Now we divide the numerator and denominator by ex.
 
[(5 + 6ex) / ex] / [(6 + 5ex) / ex] =
 
(5/ex + 6) / (6/ex + 5)
 
 
Now we plug in x=infinity into the function.  Doing so, we get a constant over some infinitely large number.  When that happens, we get a result of zero.  In other words.
 
lim     1/ex = 0
x->∞
 
Therefore,   5/ex    and   6/ex get eliminated because they result in zero when infinity is plugged into x.  Thus leaving you with
 
 
lim        6/5
x->∞
 
 
 
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09/09/16

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