(x-2)^2/9+(y-1)^2/4=1 graph the ellipse and state the center and the foci

Question

graphing 

Answer 1

your equation is in this form:

 

(X-h)/a^2 +(Y-k)/b^2 = 1

 

center (h,k) is (2,1)

 

since a^2 is under X the major axis runs horizontal 

 

C is distance from center to foci

 

C^2 = a^2 - b^2

 

C^2 = 9 - 4

 

C = √5

 

foci: (2 + √5 , 1) and (2 - √5 , 1)