Mark M. answered 09/07/16
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f(x) is an odd function is f(-x) = -f(x).
For each of the equations substitute -x. If the result is the opposite, the function is odd.
Mark M.
Not necessarily. For example
f(x) = x2
f(-x) = (-x)2 = x2
This function is even.
f(x) = x3
f(-x) = (-x)3 = -x3
This function is odd.
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09/07/16
Phil S.
Okay so switching the x's, the only function that is odd is the first one because the value isn't squared so its opposite. But I tried that as my answer and it says I was wrong, so does that mean I did something wrong in my thought process?
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09/07/16
Mark M.
Your thinking partially correct. The numerator must also be considered.
f(x) = (x - 1) / (x2 + 1)
f(-x) = (-x - 1) / (x2 + 1)
f(-x) = -(x + 1) / (x2 + 1)
Notice that the numerator is NOT the opposite of the original numerator.
None of functions are odd.
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09/07/16
Phil S.
09/07/16