Phil S.

asked • 09/07/16

Is the function Odd? How can you tell?

You are given the following functions.

(I) y = (x-1)/(x^2+1)
(II) y=(x^2-1)/(x^2+1)
(III) y=(x^2+1)/(x^2-1)
 
(d) Which of the function(s) are odd functions? (Select all that apply.)
(I)
(II)
(III)
none of these
I put one, but I am not entirely sure how to tell when it's odd like I can on other functions. They are L shaped and I am very confused on how to classify if its odd or even on these graphs. Please help me. Thank you!

1 Expert Answer

By:

Mark M. answered • 09/07/16

Tutor
5.0 (278)

Mathematics Teacher - NCLB Highly Qualified

Phil S.

What do you mean by substitute. If I change all the x's to negative wouldn't they automatically be opposite?
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09/07/16

Mark M.

Not necessarily. For example
f(x) = x2
f(-x) = (-x)2 = x2
This function is even.
f(x) = x3
f(-x) = (-x)3 = -x3
This function is odd.
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09/07/16

Phil S.

Okay so switching the x's, the only function that is odd is the first one because the value isn't squared so its opposite. But I tried that as my answer and it says I was wrong, so does that mean I did something wrong in my thought process?
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09/07/16

Mark M.

Your thinking partially correct. The numerator must also be considered.
f(x) = (x - 1) / (x2 + 1)
f(-x) = (-x - 1) / (x2 + 1)
f(-x) = -(x + 1) / (x2 + 1)
Notice that the numerator is NOT the opposite of the original numerator. 
None of functions are odd.
 
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09/07/16

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