3x/5-2=x+1/3, solve for x

Question

Please help!

Answer 1

3x/5-2=x+1/3

 

Multiply by LCM=15 to get rid of all fractions:

  9x - 30 = 15x + 5

   -6x - 30 = 5            [subtract 15x from both sides]

   -6x = 35                [add 30 to both sides]

     x  = -35/6             [divide both sides by (-6)]

     x = -5 5/6

Answer 2

3x/5 - 2 = X+ 1/3

 

multiply all terms by l.c.d. To eliminate denominators: 15

 

    9x - 30 = 15x + 5

 

         -35 = 6x

 

      -35/6 = X

 

Answer 3

3x/5-2=x+1/3, solve for x

subtract x from both sides. x can be written as 5x/5 because 5/5 = 1

* common denominators are need to add and subtract fractions

 

3x/5 - 5x/5 - 2 = x - x + 1/3

 

-2x/5 - 2 = 1/3

 

add 2 to both sides. 2 = 6/3

 

-2x/5 -2 + 2 = 1/3 + 6/3

 

-2x/5 = 7/3

 

multiple by 3 on both sides

 

3 * -2x/5 = 3 * 7/3

 

-6x/5 = 7

 

multiple by 5 on both sides

 

5 * -6x/5 = 7 * 5

 

-6x = 35

 

now divide by -6 on both sides

 

-6x/-6 = 35/-6

 

x = -5.833. . or x = -5 5/6