Kendra F. answered 08/25/16
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how long were they riding their bicycle? How many miles did they ride each way?
Let
Let
D = Distance (mi)
t = time (hr)
The route there:
8mi/hr (t) = D
The route back:
The route back:
7mi/hr (t+1hr) = D + 4mi
Substitute the first Eq. in for D in the second Eq.
7mi/hr (t+1hr) = (8mi/hr (t)) + 4mi
Units cancel out, giving t in hr.
7(t+1) = 8t + 4
Solve for t
7(t+1) = 8t + 4
7(t+1) = 8t + 4
7t + 7 = 8t + 4
7 - 4 = 8t - 7t
3 = t
It takes them 3 hrs to ride there and 4 hrs to ride back (problem states 1 hr longer)
It takes them 3 hrs to ride there and 4 hrs to ride back (problem states 1 hr longer)
Use t= 3 to find the distance traveled there and add on the 4mi to find the distance back.
8mi/hr (t) = D
8mi/hr (3hr) = 24 mi there
24 mi + 4 mi = 28 mi back