Graph this inequality y>-3x-2

Question

Please explain how you did it because I don't get it.

 

Answer 1

This type of problem is very easy:

 

First, pretend that you have an equation; draw the line (which is a half-plane's boundary). In this case, since you had y > ..., the line should be drawn as a DASHED line; if it had been y ≥ ..., the line would be 'solid,' not dashed).

 

Secondly, SHADE THE AREA ABOVE the line (above because the inequality had >; if it had <, you'd shade below).

 

Done!

Answer 2

Nathalie, to check that you've done it correctly, pick any point in your shaded region, plug in x and y, and see if it makes your equation true.

 

For example, (0,-1) should be in your shaded area...

 

-1 > -3(0) - 2

-1 > 0 - 2

- 1 > -2

 

Since this is true, we know you shaded the correct area.

 

The reason your line is dashed is because nothing along the line works. One point along the line is your y-intercept (0,-2)...

 

-2 > -3(0) - 2

-2 > 0 - 2

-2 > -2

 

Obviously, -2 is not greater than itself. As has been explained, if the sign would have been ≥, that point along your line would work because -2 = -2 and fits.

Answer 3

First graph the boundary line

 

y = -3x - 2

 

y-intercept = -2,  slope = -3

 

since the inequality sign does not have an equal sign under it your line will be drawn dashed

 

all inequalities have shading, since this says y >, you will shade above your dashed line

 

you now have graphed all y values greater than the line