William Z.

asked • 08/07/16

how would I go about proving the Helmholtz decomposition thereon?

Well my problem specifically is with the diffrential^3(r'-r) I know its not a diffrential but what is it really and how is that derived?

1 Expert Answer

By:

William Z.

But my issue is with the diffrential^3(r'-r) Im not sure what this functions as or how its derived
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08/07/16

Steven W.

tutor
That is not something that is derived; it is defined.  It is a function that equals some value (often normalized to 1) when the argument is 0, and equals zero otherwise.  In this case, it is the three-dimensional version.  What it means is that is it one is r = r' (as a vector) and zero if r is anything else.  In other words, it mathematically specifies that we are looking at a location specified by the vector r' at any point in our calculation.
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08/07/16

Steven W.

tutor
Somehow I moved right past the fact that it is called the delta function.
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08/07/16

Steven W.

tutor
Vector calculus is not my specialty, but I believe the delta function is usually used (as it is here) under integration, so that every point were r ≠ r' contributes a value of zero to the integral, leaving the only nonzero contribution to be when r = r'.
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08/07/16

William Z.

Thank you very much! That was an excellent explanation! It cleared things up tremendously.
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08/07/16

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