Y=e cosh(X/e) at (0,e)

Question

Hyperbolic function (deferential calculus 

Answer 1

Hello Jazbi,

 

I am guessing the question is to show that (0, e) is a point of the equation.

 

Hyperbolic cosine function is defined as y = cosh(x) = (e^x + e^-x)/2

 

For x = 0, y = cosh(0) = (e⁰ + e⁰⁾/2 = (1 + 1)/2 = 1

 

If the function is y = e cosh(x/e), then when x = 0, y = e cosh(0) = e * 1 = e

 

Without having a specific question to answer I am giving information about cosh function.  If there is more details or information, please let me to help clarify further.