The sum of three consecutive integers is 267, what is the largest integer?

Question

I don't understand 

Answer 1

Consecutive integers are integers that follow continuously in an unbroken or logical order. For example, 1, 2, 3, and so on.

 

Let the least integer be x. Therefore, the next two integers following this x are: (x + 1) and (x + 1 +1)

 

Sum of these three integers = 267

 

x + (X + 1) + (x + 1 + 1) = 267

 

x + (x + 1) + (x + 2) = 267

 

Combining like terms gives:

 

3x + 3 = 267

 

3x = 264

 

x = 264/3

 

x = 88

 

Therefore, the largest integer = x+ 2 

 

                                          = 88 + 2

 

                                          = 90

Answer 2

You have two algebraic solutions. Here's an arithmetic solution.

Find the mean of the three numbers. It will be the middle number.

267/3=89

89-1=88

89+1=90

88, 89, and 90 are the numbers and 90 is the largest

Answer 3

n + (n + 1) + (n + 2) = 267

3n + 3 = 267

3n = 264

n = 88

(n + 2) would be the largest integer, so that would be 90.