Nathalie M.

asked • 07/28/16

Solve the equation

(√6x+7) +3 = x+5

Jason L.

(√6x+7) +3 = x+5
√6x + 10 = x+5
(√6x)^2 = (x-5)^2
6x = x^2 - 10x +25
0 = x^2 - 16x + 25
 
Now solve using the quadratic equation.
 
16 -/+ √(-16^2 - 4(1)(25)    /   2(1)
16 -/+ √156 / 2
16 -/+ √(4*39) / 2
16-/+ 2√39  / 2
8 -/+ √39
 
 
Report

07/28/16

2 Answers By Expert Tutors

By:

Norbert W. answered • 07/28/16

Tutor
4.4 (5)

Math and Computer Language Tutor

See tutors like this
See tutors like this
(√(6)x+7) +3 = x+5
 
√(6)x + 10 = x + 5
 
(√(6) - 1)x = -5
 
x = -5/((√(6) - 1)) * (√(6) + 1)/(√(6) + 1)
   = -5 * (√(6) + 1)/5
   = -√(6) - 1
 
 
Upvote • 0 Downvote
More
Report

Norbert W.

Check that this was the correct formula.  If it was not, please use parenthesis to indicate what the actual equation was.
Report

07/28/16

Kenneth S. answered • 07/28/16

Tutor
4.8 (62)

Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018

See tutors like this
See tutors like this
I believe that the original problem has mis-parenthesization.
 

(√6x+7) +3 = x+5  probably should be   √(6x+7) +3 = x+5

in which case the student should isolate the radical on one side, then square both sides, etc
Upvote • 0 Downvote
More
Report

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.