M H.

asked • 07/25/16

Solve for x by factoring

Solve for x by factoring where 0<x≤2∏
 
Sin3x=-sin x cos2x

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Mark M. answered • 07/26/16

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sinx3 = -sinx cosx2
sinx3 + sinx cosx2 = 0
sinx(sinx2 + cosx2) = 0
sin x = 0
x ∈ {π, 2π}   (restricted domain eliminates x = 0)
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Kenneth S.

The work above uses exponents inappropriately; either write (sin x)3 or, per convention, sin3x, and so forth.
Nevertheless, the answer obtained is correct.
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07/26/16

M H.

So x is equal to 0 and 2pi?
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07/26/16

M H.

i meant pi and 2pi? 
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07/26/16

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