
Norbert W. answered 07/20/16
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Math and Computer Language Tutor
Let s be the amount of sand to added.
The pile that has 15% sand contains .15(360000) = 54000 pounds of sand.
With the sand added the total weight of concrete would be 360000 + s.
This final mixture would contain 20% sand.
This means .2(360000 + s) = 54000 + s
72000 + ,2s = 54000 + s
.8s = 18000
s = 22500 pounds of sand must be added