Mark M. answered 06/08/16
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Mathematics Teacher - NCLB Highly Qualified
0.7a0 = a0ek(3)
0.7 = e3k
ln 0.7 = 3k
-0.11889 ≈ k
0.15a0 = a0e(-0.11889)t
0.15 = e-011889t
ln 0.15 = -0.11889t
-1.8971 ≈ -0.11889t
15.9596 ≈ t