f(x)=3x^2+2x+1,f'(0)=?

Question

f(x)=3x^2+2x+1,f'(0)=

(a) 5
(b) 2
(C) 1
(d)-2

Answer 1

F'(x)=6x+2

substitute 0 => 2(choice B)

Answer 2

I believe this is calculus problem, you are looking for f'(0) not f(0) correct? The derivative of f at 0? In that case, f'(x)=6x+2, so f'(0)=2. b.

Answer 3

 

We find f(0) by substituting 0 for all occurrences of x in our function.

 

f(0) = 3(0)² + 2(0) + 1

       = 0 + 0 + 1

       = 1

 

Answer is C