
Arturo O. answered 05/24/16
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Let x and y be the two numbers.
xy = 16
Let z = x^2 + y^2
We want to minimize z. Let us make z a function of a single variable, say x, then differentiate z and set the derivative equal to 0, solve for x, and then solve for y:
xy = 16 implies y = 16/x
z = x^2 + y^2 = x^2 + (16/x)^2 = x^2 + 256 / x^2
dz/dx = 2x - 512 / x^3 = 0
2x = 512 / x^3
2 x^4 = 512
x^4 = 512/2 = 256
x = 256^(1/4) = 4
y = 16/x = 16/4 = 4
Helen J.
05/24/16