First, it is important to note that the half life of carbon-14 is 5730 years. This says that the amount of carbon is exponentially related to the length since decay began. To start, note that half life is represented by equation 1 below:

Equation 1:

A(t)=A*e^{kt/t1/2}

This says that the amount left is equal to the initial amount multiplied by e raise to the power of the k (the decay constant) and the number of half lives, or simply t/t_{1/2; }where t is the time (age) and t_{1/2} is the half lift of the subject.

If you are unfamiliar with the k constant for carbon-14, then it can be solved by plugging in a known value: the time of the half life, or t/t_{1/2}=1. Since the time you plug in at this point is the half life of the substance, then A(t)=(1/2)*A.

Then you have:

.5A=A*e^{k}

solving you get:

.5=e^{k}

To find k, you simply take the natural log (ln) of both sides.

ln(.5)=-.693

Now that you have k, it is a matter of substituting the amount of carbon-14 left at the age you would like to calculate.

So,

.46A=A*e^{-.693*t/5730}

Notice that the A's cancel out and you get:

.46=e^{-.693t/5730 }or .46=e^{-.00012t}

Take the natural log (ln) of both sides to eliminate e and you have

ln(.46)=-.00012t

Solving for t you get:

t=-ln(.46)/.00012 = 6471 years