David W. answered 05/18/16
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Let's try to picture the future days:
1: xExEx ExExE xExEx ExExE xExEx ExExE
2: xxExx ExxEx xExxE xxExx ExxEx xExxE
3: xxxxE xxxxE xxxxE xxxxE xxxxE xxxxE
2 2 2 2 2 2 2
2 at positions: 6, 10, 12, 15, 18, 20, 24
Since the LCM (Least Common Multiple) of (2,3,5) is 30, the next 30 values will have the same pattern, and the next 30 and the next 30. So, in 101 days, there will be 3 sets of 30 days (with 7 days of 2 eggs) and a smaller set of 11 days (with 2 days of 2 eggs). That’s a total of (3*7 + 2)=23 days of exactly2 eggs.
2 2 2 2 2 2 2
2 at positions: 6, 10, 12, 15, 18, 20, 24
Since the LCM (Least Common Multiple) of (2,3,5) is 30, the next 30 values will have the same pattern, and the next 30 and the next 30. So, in 101 days, there will be 3 sets of 30 days (with 7 days of 2 eggs) and a smaller set of 11 days (with 2 days of 2 eggs). That’s a total of (3*7 + 2)=23 days of exactly2 eggs.