Leslie S.

asked • 05/16/16

Pre Calculus

Given the center, a vertex, and one focus, find an equation for the hyperbola: center: (4, −2); vertex (4, 2); one focus (4, -2+4√5)

1 Expert Answer

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Alan G. answered • 05/17/16

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Leslie S.

Once I plug that in, is my equation (y+2)2/(16)-(x-4)2/(64)=1? 
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05/17/16

Alan G.

Yes, it looks correct.
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05/17/16

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