The vertices of triangle IJK are I(0, 0), J(0, 100) and K(200, 0). Find the length of JI.If necessary, round your answer to the nearest tenth.

Question

please help

Answer 1

JI = 100

KI= 200

JK =sqr(200^2 + 100^2 = sqr(40000+10000) = sqr(50,000) = 100sqr5 = about 100(2.2) = 220

JK is the hypotenuse, KI is the base, JI is the height of the triangle