A triangle has vertices A(-2, -2), B(0, -9) and C(1, 2). Find BC. If necessary, round to the nearest hundredth.

Question

please help

Answer 1

BC is the distance from point B(0, -9) to point C(1, 2). Use the distance formula to find BC.

 

d = sqrt[(x2 - x1)² + (y2 - y1)²]

x2 = 1       x1 = 0

y2 = 2        y1 = -9

 

 

d = sqrt{(1 - 0)² + [2 - (-9)]²}

 

   = sqrt(1² + 11²)

 

   = sqrt(1 + 121)

 

   = sqrt(123)

 

   = 11.09

 

So BC = 11.09