solve the equation 4^x^2-80=16^x

4^x^2-80=16^x submitted. I am going to assume

4x

^{2}-80=16x or 4x^{2}-16x-80=0 is what is intendeddivide by 4 to get x

^{2}-4x-20=0 whose solution by formula is(4±√(16+80))/2=2±2√6

As for the form submitted, graph it. It's tall skinny slightly lopsided "v"

## Comments

^{(X^2 -80 )}= 4^{2x},^{2}- 80 = 2X^{2}- 2X - 80 =^{X})^{2}- 80^{ = }4^{2x }