solve the equation 4^x^2-80=16^x

Question

solve the equation 4^x^2-80=16^x

Answer 1

4^x^2-80=16^x  submitted.  I am going to assume

4x²-80=16x or      4x²-16x-80=0 is what is intended

divide by 4 to get x²-4x-20=0 whose solution by formula is

(4±√(16+80))/2=2±2√6

As for the form submitted, graph it.  It's tall skinny slightly lopsided "v"

Answer 2

Just to clarify, is this the problem you are trying to answer?

 

4^{x^2} - 80 = 16^x

 

As in, 4 raised to the power x² minus 80 equals 16 raised to the power x?

 

OR

 

Do you mean:

 

4^{x^2 - 80} = 16^x

 

As in, 4 raised to the power x² -80 equals 16 raised to the power x?

 

-Bailey S.

Answer 3

 

 

 You should write the problem properly place a parenthesis whenever you want to raise an expression to an exponent.