how many gallons y of a 50% solution must be mixed with x gallons of a 20% salt solution to produce 10 gallons of a 38% salt solution. set up with two equations

y = gallons of a 50% solution

x = gallons of a 20% solution

**equation 1**

x+y=10

10 gallons are produced between the two solutions, which means you need to start with a total of 10 gallons.

**equation 2**

.5y + .2x = .38(10)

## Comments

equation 2.5y + .2x = .38(10)

This equation is finding the correct ratio of the two solutions which must be used.