Roman C. answered 05/06/16
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Masters of Education Graduate with Mathematics Expertise
CLT says that if you sample from a population with a finite mean μ and finite standard deviation σ, then the distribution of the sample mean approaches the Normal distribution, with mean μ and standard deviation σ/√n.
More precisely, it says that z = (xbar - μ) / (σ/√n) → N(0,1) as n → ∞.
In our case, the sample mean of will be approximately Normal with:
Mean: 12
Std. Dev.: 2/11