Arthur D. answered 05/02/16
Tutor
4.9
(274)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
f(1)=3
f(n)=-2f(n-1)+1
f(1)=-2f(1-1)+1
f(1)=-2f(0)+1, 3=-2f(0)+1, 3-1=-2f(0), 2=-2f(0), -1=f(0)
f(0)=-1
f(1)=3
f(2)=-2f(2-1)+1, f(2)=-2f(1)+1, f(2)=-2(3)+1, f(2)=-6+1, f(2)=-5
f(3)=-2f(3-1)+1, f(3)=-2f(2)+1, f(3)=-2(-5)+1, f(3)=10+1, f(3)=11
f(4)=-2f(4-1)+1, f(4)=-2f(3)+1, f(4)=-2(11)+1, f(4)=-22+1, f(4)=-21
f(5)=-2f(5-1)+1, f(5)=-2f(4)+1, f(5)=-2(-21)+1, f(5)=42+1, f(5)=43
f(5)=43 (answer)