Mark M. answered 04/30/16
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Retired math prof. Very extensive Precalculus tutoring experience.
(x-1)/(x+2) > 2
(x-1)/(x+2) - 2 > 0
[(x-1)-2(x+2)]/(x+2) > 0
(-x-5)/(x+2) > 0
numerator = 0 when x = -5 denominator = 0 when x = -2
__________l____________l__________
-5 -2
When x < -5, (-x-5)/(x+2) < 0
When -5<x<-2, (-x-5)/(x+2) > 0
When x>-2, (-x-5)/(x+2) < 0
Solution set: -5 < x < -2 Interval notation: (-5,-2)