3(R+-9)+9=-3 need help finding the "R" (-)= negative

Question

i really dont know how to solve this problem, i dont even where to start at.

Answer 1

3( R- 9 ) + 9= -3

 

R  - 9 + 3 = -1   / divide both sides by 3

 

R = 6 - 1 = 5     / add 6 to both sides of equation.

 

  Be always observant , and simplify.

 

 

Answer 2

3(R +  -9)  + 9  =  -3

 

You can start working on what is inside the bracket.  Everything in the bracket is to be multiplied  by 3.  By doing this you will be removing the bracket.

 

1. 3  x  R  =  3R
2.     +
3. 3  x  -9 =  -27

Put them back together with the   +9

4. 3R  - 27   + 9

 

Then make the equation complete by showing that everything =  - 3

 

5. 3R  -29  +9  =  -3       

Note   [9-27=18]

6. 3R   - 18      =  -3

 

Put the numbers together, remember when a number of letter crosses over the = sign,

I call it crossing over the bridge, the sign changes

 

8)  3R  =  -3 + 18

9)  3R  =  15

Divide both sides by 3

 

10) 3R ÷ 3    =  15 ÷ 3

11)   R          =   5  

 

 

Answer R=5

Answer 3

 

The first step is to multiply the 3 into the parenthesis

 

3R-27+9=-3

 

3R-18=-3

 

Divide the whole equation by 3 to get R by itself

 

R-6=-1

 

R=5

Answer 4

(R+-9)=(R-9)

3(R-9)+9=-3

3R-27+9=-3

3R-18=-3

3R=18-3

3R=15

R=5, or

 

3(R+-9)+9=-3

3R+(3)(-9)+9=-3

3R-27+9=-3

3R-18=-3

3R=18-3

3R=15

R=5