find a if ax^2 + 8x +32 =0

Question

Find the value of a so that the equation ax²+8x +32 =0 has 1 real root

 

 

Answer 1

find a if ax² + 8x +32 = 0

 

If a quadratic equation has exactly one real root, then its discriminant must equal 0.

b² - 4ac = 0 means, in this case, 8² - 4a(32) = 0.

64 = 128a

a = ½.