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Given f(x)=(x+5)^3. (a) Determine whether f(x) is one-to-one. (b) Find a formula for its inverse. (c) Graph f(x) and f^(-1) (x) on the same axis.

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Jason S. | My goal is the success of my students. Knowledge-Patience-HonestyMy goal is the success of my students. K...
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You can graph the function and if it passes the vertical line test, it's one-to-one.
Does f(a) = f(b) imply that a=b?
f(a) = (a+5)^3
f(b) = (b+5)^3
If (a+5)^3 = (b+5)^3...
Cube root of both sides:
a+5 = b+5
Subtract 5 from both sides:
a = b.   It's one-to-one.
Note that the parent function is y = x^3, which is one-to-one.
It is shifted 5 units to the left, so it crosses the x axis at (-5, 0).  Down to the left and up to the right.
To get the inverse function, exchange x and y and solve for y:
x = (y+5)^3
Take the cube root of both sides:
x^(1/3) = y+5
y = x1/3 - 5
If they are inverses, once you graph them, they should be reflections of each other across the line y=x.