
Andrew M. answered 04/22/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
We have 165 students that are neither in Rollins' class nor in honors
33/56 of the nonhonors students is 165
Let N = # nonhonor students
(33/56)N = 165
N = 165(56)/33 = 280 total nonhonors students
Since there are 280 total nonhonors students and
165 of then are not in Rollins' class... Then
280-165 = 115 nonhonors students ARE in Rollins' class
Then 23/51 of Rollins students = 115
Let R = # students in Rollins class
(23/51)R = 115
R = 115(51)/23 = 255 total students in Rollins' class
Of that 255 we have 115 that are not in honors
leaving 140 honors students in Rollins class