find the vertex of y=x^2+5

Question

find the ordered pair for the vertex. this is all the question consist of. this is an algebra 1 question

Answer 1

First let's define vertex: A point on the curve with a local minimum or maximum of curvature.

 

If we look for the minimum and maximum value of the equation y=x^2+5:

 

minimum value X=0, substitute in the equation to get the maximum value of Y

 

y = 0^2 + 5

y = 0 + 5

y= 5

 

so the ordered pair is (0,5)

 

I have included the graph to help visualize the answer.

 

Hope this helps!