Hannah M.

asked • 04/19/16

Geometry Question

A square and an equilateral triangle each have apothem of length 1cm. Which of the following statements is always true?
I: The perimeter of the square is greater than the perimeter of the triangle.
II: The area of the square is less than the area of the triangle.
III: The radius of the square is less than the radius of the triangle.
a. I only
b. II only
c. I and II only
d. II and III only

2 Answers By Expert Tutors

By:

Richard W. answered • 04/24/16

Tutor
5.0 (51)

Retired H.S. Math Teacher: Effective help in Algebra 1 and Geometry

Hannah M.

Thank you for clarifying! I think that I may be finally understanding this!
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04/25/16

Hannah M.

Thank you very much for your help! I appreciate that you took your time to answer this question. I also got the answer A. However, my teacher marked it wrong and said the answer is D. So I was confused. That is why I posted the question on WyZant. I am trying to understand how to do this problem. My geometry course is online so I have to email everything to my teacher. Do you see any mistakes in her calculations for why she would be saying D? Thank you again for your assistance!
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04/21/16

Joseph C.

tutor
Thank you for your response. It is always gratifying to hear from students.
I am unable to explain your teacher's selection. Your only choice is to write to her, and request an explanation.
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04/21/16

Hannah M.

I will do so. It is interesting... two other experts in math also came up with A for the answer.
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04/21/16

Joseph C.

tutor
I will be interested in her response. Please send it to me.
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04/21/16

Hannah M.

Here is what my teacher told me:
 
"The most direct way to do this is to calculate perimeter and area of each.
For the square, since the apothem is 1 cm and that is from the center to a side, the entire length of a side is 2cm. So, the perimeter of the square is 2+2+2+2=8 and the area of the square is 2*2=4. To find the radius, make a right triangle with the apothem as one leg (1) and half of one side as the other (1). Then, use the Pythagorean Theorem to find the radius(hypotenuse) at √2.
For the equilateral triangle, use the apothem as one leg, then the radius would be the length from the center to one of the vertices, making a 30-60-90 triangle. The short leg (apothem) is 1, so the radius (hypotenuse) would be 2 and half of one side would be √3. The perimeter then is 6√3. To find the height, add the apothem to the length of the radius = 3. The area is ½bh = ½(2√3)(3) = 3√3.
Summarizing
Square
Perimeter: 8
Area: 4
Radius: √2≈1.4

Equilateral Triangle
Perimeter: 6√3≈10.4
Area: 3√3≈5.2
Radius: 2

So, the perimeter of the square is less. The area of the square is less. The radius of the square is less. So, d is the correct answer."
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04/23/16

Joseph C.

tutor
I understand her answer, and the reason is that  there are actually two radii in an equilateral triangle. There is the inscribed circle where the radius is equal to the apothem. Then there is a circumcircle (circumscribed circle) where the radius is equal to twice the apothem, and it extends from the center to one of the vertices. 
 
Given the second case, her answer is correct.  The problem statement did not clarify which circle was meant.
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04/23/16

Hannah M.

Thank you for explaining this to me.
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04/24/16

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