passing through (3,-7) and perpendicular to the line whose equation is x-7y-2=0

Question

i need help to pass my math class in college

Answer 1

x-7y-2=0

-7y=-x+2

y=x*1/7 -2

so, slope of this line = 1/7

therefore, slope of a line perpendicular to the above line = -7 ( as product of slopes of two perpendicular lines = -1 )

 

Now, the second line has a slope = -7 and passes through 3,-7

 

equation is ( y-b)=m(x-a) where m = slope and passes through a,b

 

y- (-7) = -7 ( x-3 )

y+7 = -7x+21

 

7x+y-14 = 0 is the answer