One number is one less than a second number.Four times the first is 8 more than 6 times the second.Find the

Question

 I need some help asap.

Answer 1

a = first number and b = second number

 

One number is one less than a second number ===> a = b-1 (A)

Four times the first is 8 more than 6 times the second ===> 4a = 8+6b (B)

 

Substitute A in B we get

4b-4 = 8 + 6b

2b=-12 ===> b = -6

a=b-1 = -6-1 = -7