
Andrew M. answered 04/15/16
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
One number is 8 times another.
x = 8y
The sum of their reciprocals is 27/8.
1/x + 1/y = 27/8
We can substitute 8y in place of x in the 2nd equation
in order to solve for y
1/8y + 1/y = 27/8
1/8y + 8/8y = 27/8
9/8y = 27/8
Cross multiply
27(8y) = 9(8)
216y = 72
y = 72/216
y = 1/3
x = 8y = 8(1/3) = 8/3
Your numbers are 8/3 and 1/3
Check:
1/x + 1/y = 27/8
1/(8/3) + 1/(1/3) = 27/8
3/8 + 3 = 27/8
3/8 + 24/8 = 27/8
27/8 = 27/8
Equation balances and answer is correct.

Andrew M.
04/15/16