If f(4)=246.4 when r=0.04 for f(t)= pe^rt, then what is the approximate value of p

Question

I need help with this problem as soon as possible please and thank you 

Answer 1

f(t) = pe^rt

f(t) = pe^(0.04)t

f(4) = pe^(0.04)(4)

f(4) = pe^(0.16)

246 = pe^(0.16)

ln 246 = ln [pe^(0.16)]

ln 246 = ln p + ln e^(0.16)

ln 246 = ln p + 0.16

5.50533 ≈ ln p + 0.16

5.34533 ≈ ln p

209.627 ≈ p