I am going to assume 'c' in your equation refers to the confidence level.
The question asks you to find a 90% confidence interval for the true population mean based on a random sample of size (n) 40 with a sample mean test grade of 81.5 and sample standard deviation (sd) of 10.2.
Since the sample size is greater than 30, the central limit theorem can be used to construct confidence interval for the true mean. The formula for obtaining the confidence interval is:
sample mean -/+ z0.9 * sd/(n)0.5 ,where z0.9 is the 90th percentile for the standard normal distribution. z0.9 is equal 1.644854. Plugging in the unkowns in the above formula, you get the answer you are looking for.
I hope this helps.
Kidane