We are given that there is a rectangle (40m x 30m) in which there is another rectangle.
The Area of the given rectangle is 1200m2, and the desired Area of the inner rectangle must be 600m2 in order "that they share work equally."
let x = width of the strip, then, since Area = Length x Width,
we get 600m2 = (40m - x) • (30 - x)
expanding, we get 600 = 1200 - 70x + x2
combining terms, we get x2 - 70x + 600 = 0
factoring, we get (x - 10)(x - 60) = 0
so, x can equal 10, or 60. But we will discard the 60 value because it is larger than the given dimensions.
so, x = 10m, and 40m - 10m = 30m; 30m - 10m = 20m
Thus, 30m • 20m = 600m2
the strip has to be 10m wide.