^{1}/

_{x+3}-

^{x}/

_{x-2}+

^{x^2+2}/

_{x^2-x-2 }(used super/subscript and "/" to show fraction. Not sure if that's proper format)

Tutors, please sign in to answer this question.

Los Angeles, CA

first factor x^{2}-x-2 to get (x-2)(x+1). The reason I factored it was to determine what's going to be my LCD. With that being said my LCD therefore is: LCD: (x+3)(x-2)(x+1). Notice that (x-2) was a repeated factor but you only account for it once.

...1/x+3 goes into the LCD (x+3) times so you multiply the numerator which is 1 by the remaining factors (x-2)(x+1). we get (x+2)(x+1)/LCD...x^{2}-x-2/LCD

...x/x-2 goes in the LCD (x-2) ties so u multiply the numerator x by (x+3)(x+1). we get x(x+3)(x+1). multiply everything out to get x^{3}-4x^{2}-3x/LCD.(remember to multiply by negative 1)

...x^{2}+2/x^{2}-x-2 goes in the LCD (x-2)(x+1) times so multiply the numerator x^{2}+2 times the remaining factor x+3.

we get. x^{3}+3x^{2}+2x+6.

Now that we have found the LCD we can perform the indicated operations. so the final answer after collecting like terms is...-2x+4/LCD.. the cubic and quadratic factors will cancel out.

now in your numerator, divide it by -2 to get x-2.

so we no have x-2/(x+3)(x+1)(x-2)

Notice that (x-2) cancels so the final answer is ......................1/(x+3)(x+1)

John E.

Physics and Math tutor - Masters from Cornell and Columbia University

New York, NY

4.8
(124 ratings)

Randy R.

Middle and High School Math, Chemistry, General Science

Nutley, NJ

4.9
(127 ratings)

John K.

Ardent Mathematics, Science, History, SAT and German Polymath

College Point, NY

5.0
(50 ratings)

- Math Help 3989
- Algebra 3770
- Calculus 1704
- Math Word Problem 2817
- Algebra 2 2689
- Word Problem 3762
- Algebra 1 3047
- Math Equations 856
- Math Problem 736
- Math Help For College 1159

Find a tutor fast. Get the app.

Are you a tutor? Get the app for tutors

© 2005 - 2016 WyzAnt, Inc. - All Rights Reserved

## Comments