Alan G. answered 03/18/16
Tutor
5
(4)
Successful at helping students improve in math!
Let x be the cost of one day lily and y the cost of one pot of ivy.
Then,
230 = 14x + 10y
118 = 10x + 2y.
You must solve this system of equations. Here is one way to do it.
230 = 14x + 10y → 230 = 14x + 10y
-5 ( 118 = 10x + 2y ) → -590 = -50x - 10y
The add together: -360 = -36x → x = 10.
Plug this into one of the original equations to solve for y.
118 = 10(10) + 2y → 2y = 18 → y = 9.
They bought 10 day lilies and 9 ivy pots.
You can check this in the original problem statement.