Find the equation if a parabola with a vertex (4,8) passes through the origin.

Question

This problem is a writing quadratic functions. HELP

Answer 1

With vertex (h,k) the formula will be

y = a(x-h)² + k

 

y = a(x-4)² + 8

Is the basic formula.  We need to find the value of "a"

 

We know it passes through (0,0) so

0 = a(0-4)² + 8

0 = 16a + 8

16a = -8

a = -8/16

a = -1/2

 

Your equation is:  y = (-1/2)(x-4)² + 8